User:Burner

$\alpha \wedge \omega$

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$\sum_{i=1}^{10}{i^2} = 1^2+2^2+3^2+4^2+5^2+6^2+7^2+8^2+9^2+10^2 = 1+4+9+16+25+36+49+64+81+100$

$\prod_{i=1}^{4}{2^i} = 2^1\cdot2^2\cdot2^3\cdot2^4 = 2^{1+2+3+4} = 2^{10} = 1024$

--MichaelHead 13:55, 29 Dec 2005 (EST)

$\sum_{i=1}^{\infty}{i\over 2^{i+1}} = {1\over 4} + {2\over 8} + {3\over 16} + {4\over 32} + {5\over 64} + {6\over 128} +\cdots$

$= {1\over 4} + {1\over 8} + {1\over 16} + \cdots + {1\over 8} + {1\over 16} + \cdots + {1\over 16} + \cdots + \cdots$

$= {1\over 2} + {1 \over 4} + {1\over 8} \cdots = 1 = 0.999...$

$a 2 + b 2 = c 2$

--Burner 00:57, 20 December 2007 (EST)